12g of hydrogen peroxide catalyzed to yield water and oxygen air at S.T.P.
i. The volume of water formed.
ii. The volume of oxygen formed.
Convert 12g of H2O2 into mole
i. Find the volume of water formed.
The chemical equation for the reaction2(H2O2)(g) → catalase 2H2(l) + O2(g) catalyst
Make mole equivalent between H2O2 and water (H2O)
2 moles of (H2O2) Ξ 2 moles of H2O
0.3529 moles of (H2O2) Ξ ?? of H2O
= (0.3529 mole × 2 mole) / 2 moles
= 0.352941179 mole of H2O
Convert 0.352941176 of H2O into volume
Volume = mole × molar volume
= 0.352941176 mole × 22.4dm3/mole
7.9dm3 of water was formed at S.T.P
ii/ Calculate the volume of oxygen gas formed
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