The decomposition of Pb(NO3)2 is as shown below.
Pb(NO3)2(S)→2PbO(S) + 4NO2(g) + O2(g)
If 0.01 mole of the nitrate was used, what would be the maximum volume of oxygen gas collected at room temperature and pressure?
(molar gas volume at rtp = 24.0 cm33)
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