ELECTROLYSIS-QN13
A steady of 4A was passed through an aqueous solution of copper (II) sulphate for 30 minutes. Calculate the mass of copper deposited at cathode in
-
Soln:
Data:
Current (I) = 4A
Charge of Cu = 2
F = 96500
Mw = 63.5
Time = 30 minutes (1800 sec)
Mass = MQ / V.F
M = (63.5 × 4 × 1800) / (2 × 96500)
= 2.32g
The mass of copper was 2.32
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