CHEMISTRY | QN 01 | MOLE CONCEPT
What volume of water will be produced at room temperature and pressure when 2g of hydrogen is burnt in air?
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Data:
Mass of hydrogen gas (H2) = 2g
Molar volume at room temperature and pressure = 24 dm3
Asked: volume of water
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Chemical equation for the reaction.
2H2(g) + O2(g) → 2H2O(L)
Mole ratio 2:1:2 -
To convert 2g of H2 into moles then to relate
Mole = mass/Molar mass
= 2g / 2g/mole
= 1 mole of H2
Mole equivalent between H2 and water.
2moles of H2 Ξ 2 moles of H2O
1mole of H Ξ ?? of H2
= (1 moles × 2 moles) / 2 moles
= 1 mole of H2 -
To convert 1 mole of H2O into volume of water.
Mole = volume / Molar volume
Volume = mole × molar volume
= 1 mole × 24dm3/mole
= 24dm3
24dm3 of water was produced at S.T.P.
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Prepared By:
Sir Mahame
Biology & Chemistry teacher,
Mapambano Education Center | Mwenge | DSM.
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