Data:

Volume = 1 dm³
Molar Volume of S.T.P = 22.4 dm³
Asked:
i. Volume of hydrogen chloride formed
ii. Mass of hydrogen chloride formed
iii. Moles of hydrogen chloride formed.

The balance chemical equation for the reaction
H₂(g) + CL₂(g) → 2HCL(g)

i/ Calculate Volume of H₂ produced.

Mole = Volume / Molar volume
= 1dm³ / 22.4dm³/ mole
= 0.04464 mole of H₂

Make the mole equivalent between H₂ and HCL

1 Mole of H₂ Ξ 2 Mole of HCL
0.0446mole of H₂ Ξ ?? of H₂

= (0.0446 moles × 2moles) / 1 moles
= 0.0892 mole of HCL

Convert 0.0892 moles of HCL into volume

Volume = mole × molar volume at S.T.P
= 0.0892 mole × 22.4dm³/mole
= 2dm³
2dm³ of hydrogen chloride gas was formed

ii/ Calculate the mass of hydrogen Chloride formed

use the equivalent moles between H2 and HCL formed
1 mole of H₂ Ξ 2 moles of HCL
0.0446 mole of H₂ Ξ ?? of HCL

= (0.0446 mole × 2 mole) / 1 mole
= 0.0446 mole of HCL

convert 0.0446 mole of HCL into mass
Mass = mole × molar mass
Mass = 0.0446 mole × 36.5 g/mole
= 1.6279g
1.6279g of hydrogen chloride was formed.

iii/ Calculate the moles of hydrogen chloride formed.

From mole equivalent between H₂ and HCL

1 mole of H₂ Ξ 2 mole of HCL
0.0446 mole of H₂ Ξ ?? of HCL

= (0.0446 mole × 2 moles) / 1 mole
= 0.0446mole of HCL

0.0446 mole of hydrogen chloride was formed