CHEMISTRY | MOLE CONCEPT | Question 16
Consider the reaction of C6H2 + Br2 → C6H5Br + HBr
a) What is the liming reagent if 42.1g of C6H6 react with 73.0g of Br2?
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DATA:
Mass of C6H6 = 42.1g
Mass of Br2 = 73.0g
Molar mass of C6H6 = 78g/mole
Molar mass of Br2 = 156g/mole
Chemical Equation C6H6 + Br2 + C6H5Br+HBr
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The limiting reagent
To find mole of C6H6
Mole = mass / Molar mass
= 42.1g / 78g/mole
= 0.53846 mole
Mole ratio = 0.53846 mole / 1mole
= 0.53846 mole
Mole for Br2
Mole = mass / Molar mass
= 73.0g / 156g/mole
= 0.4679 mole
Mole ratio = 0.4679 mole / 1 mole
The limiting reagent is bromine gas (Br2)
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