CHEMISTRY | MOLE CONCEPT | Question 22
Ammonium chloride reacts with calcium hydroxide as shown in the following equation.
NH4(aq) + Ca(OH)2(aq) → NH3 + CaCl2(aq) + H2(l)
Calculate the mass of ammonium chloride NH4CI that will read completely with 14.8g of calcium hydroxide.
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Mass of Ca(OH)2 = 14.8g
Molar mass of Ca(OH)2= 74g
Equation
2NH4Cl + Ca(OH)2 →2NH3 + Cacl2 + 2H2O
To convert 14.8g into moles
Mole = mass / Molar mass
= 14.8g / 74g/mole
= 0.2 mole
1 mole of Ca(OH)2Ξ 2 moles of NH4Cl
0.2 mole Ca(0H)2 Ξ ??
(0.2 mole × 2 moles) / 1 mole
= 0.4 mole of NH4Cl
Mass = 0.4 × 53.5
= 21.4g
21.4g of ammonium chloride was reacted with calcium hydroxide
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