CHEMISTRY | MOLE CONCEPT | Question 24
4.90g of copper (II) Oxide yielded 3.92g of copper when reduced by hydrogen gas.
Calculate the mass of copper (II) oxide required to yield 4g of copper. (Cu=64, O=16)
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Data
Mass1 of CuO = 4.90g
Mass1 of Cu = 3.92g
Mass2 of CuO = ?
Mass2 of Cu = 4g
To use mass equivalent between CuO and Cu produced
4.90g CuO Ξ 3.92g Cu
?? CuO Ξ 4gCu
= (4.9g × 4g) / 3.92g
= 5.0g
5.0g of copper (11) oxide (CUO) was used to form 4g
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