CHEMISTRY | MOLE CONCEPT | Question 27
1.63g of Zinc metal was added to excess Silver Nitrate Solution. The mass of silver formed was 5.40g.
(Zn = 65, Ag = 108)
What is the equation for the displacement reaction?
Show the working.
-
Data
Mass of Zn = 1.63g
Mass of Ag = 5.40g
Asked:
How silver was formed
Equation
Zn(s) + 2AgNo3(aq) → 2Ag(s) + Zn(No3)2(aq)
To convert 1.63g of Zn into moles
Mole = mass / Molar mass of Zn
= 1.63g / 65g/mole
= 0.025076 mole of Zn
To show mole equivalent between Zn and Ag
1 mole of Zn Ξ 2 moles of Ag
0.025 of Zn Ξ ?? of Ag
= (0.25 mole × 1 mole 2) / 1 mole
= 0.05 mole
Mass of Ag = mole × molar mass
= 0.05 × 108
= 5.4166g
The mass of silver formed was 5.4166g
More questions
CHEMISTRY questions are much EASIER when you clearly understand the concept. With Smart Darasa exprole concepts in fun and interactive way.
Learn more »Send Your CHEMISTRY Question
Are you a STUDENT | PARENT | TEACHER, Send your CHEMISTRY question for FREE and we will get back to you with the solution or relavant link with similar question. We receive questions every day from 08:00hrs to 16:00 EAT. Depend on volume of questions, we send solutions the same day from 18:00hrs to 20:00hrs EAT or later next day.