Volumetric-QN08
0.4 m of dilute sulphuric acid was reacted with sodium carbonate in the experimental done in chemistry laboratory
i) Work out mean volume
ii) Write the balance chemical equation
iii) What is the number of moles for?
a. Base reacted
b. Acid reacted
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Soln:
i) The average volume (A.V)
Average volume = (VI + VII + VIII) / 3
= (24.90 + 14.90 + 25.20) cm3 / 3
= 25.00cm3
The average volume was found to be 25.00cm3
ii) To write the balanced chemical equation
HSO4(aq) + Na2CO3(aq) → Na2SO4aq + H2O(I) + CO2(g)
iii) a. To find the number of base reacted from molecule equivalent
1 mole of H2SO4 Ξ 1 mole of Na2SO3
0.01 mole of H2SO4 Ξ ??
= (0.01 mole × 1 mole) / 1
= 0.01
0.01 mole of base was reacted in Experiment.
b. To find the number of acid reacted
Na = MaVa
= 0.4 M × 0.025 dm3
= 0.01 mole
The number of moles of acid reacted was 0.01 mole
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Prepared By:
Sir Mahame
Biology & Chemistry teacher,
Mapambano Education Center | Mwenge | DSM.
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