Volumetric-QN09
The experiment was done by reacting 25ml of 0.1 M sodium hydroxide with hydrochloric acid.
The product formed were sodium chloride and water.
The burette reading was 25ml.
Calculate the molarity of hydrochloric acid.
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Soln:
The balance chemical equation.
NaOH(aq) + HCl(aq)→ NaCl(aq) + H2O(l)
1 mole 1 mole 1 mole 1 mole
Molarity of NaOH = 0.1 M
Volume of NaOH = 25 ml
Molarity of HCl = ?
Volume of HCl = 25 ml
Number of HCl = 1
Number of HCl = 1
MaVa / MbVb = na / nb
MHCl = (MNaOH × VNaOH × nHCl) / VHCl × nNaOH
= (0.1 M × 25ml × 1) / (25 ml × 1)
= 0.1 M
The molarity of hydrochloric acid was 0.1 M.
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